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Configuration = 20
cycles = (10 3 1 8 2)(9 6 4 7 5)

a = 1, b = 4, c = 7
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cycles = (10 6 4 2 9 3 1 8 5)(7)

a = 2, b = 5, c = 10
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cycles = (10)(9 7 3)(8 1 5 2 6)(4)

a = 1, b = 5, c = 8
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cycles = (10)(9 3 6)(8 5 2)(7)(4)(1)

a = 3, b = 6, c = 9
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cycles = (10)(9)(8 2 5)(7)(6)(4)(3)(1)